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scat
furry -rating:g

Artist

  • ? mochisunira 16

Copyrights

  • ? umineko no naku koro ni 10k
  • ? ↳ alliance of the golden witch 36

Character

  • ? ushiromiya ange 1.7k

General

  • ? 1girl 6.8M
  • ? black eyes 266k
  • ? boots 567k
  • ? breast hold 21k
  • ? breasts 3.9M
  • ? bullying 1.1k
  • ? chalkboard 11k
  • ? cleavage 1.1M
  • ? covering privates 49k
  • ? crying 89k
  • ? crying with eyes open 42k
  • ? embarrassed 110k
  • ? empty eyes 38k
  • ? female pubic hair 98k
  • ? hair bobbles 59k
  • ? hair ornament 1.6M
  • ? humiliation 4.3k
  • ? large breasts 1.8M
  • ? math 1.2k
  • ? nude 556k
  • ? ominous shadow 206
  • ? pubic hair 152k
  • ? pussy 409k
  • ? red hair 598k
  • ? shadow 134k
  • ? solo 5.6M
  • ? strip game 367
  • ? tears 255k
  • ? thighhighs 1.3M

Meta

  • ? bad id 1.3M
  • ? ↳ bad pixiv id 996k
  • ? highres 6.2M
  • ? translated 587k

Information

  • ID: 434845
  • Uploader: 15312134215123141 »
  • Date: over 16 years ago
  • Size: 482 KB .jpg (900x1200) »
  • Source: pixiv.net/artworks/3226681 »
  • Rating: Explicit
  • Score: 85
  • Favorites: 198
  • Status: Active

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Resized to 94% of original (view original)
ushiromiya ange (umineko no naku koro ni and 1 more) drawn by mochisunira
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  • Comments
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    Mizuho
    over 16 years ago
    [hidden]

    Strip algebra?

    2 Reply
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    windward
    over 16 years ago
    [hidden]

    Yeah, Japanese people use check marks for wrong answers and circles for right ones. All but the simplest question were answered incorrectly.

    6 Reply
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    Zack
    over 16 years ago
    [hidden]

    What I don't get is, is it the teacher bullying the students and the students getting pay back or is it the students just bullying the teacher?

    -3 Reply
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    [deleted]
    over 16 years ago
    [hidden]

    [deleted]

    Deleted by 15312134215123141 over 4 years ago

    10half
    over 16 years ago
    [hidden]

    Mizuho said:
    Strip algebra?

    Crap. *leaves all his garments on the table and walks away naked, throwing hands in the air*
    Fucking algebra.

    7 Reply
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    pepe1220
    over 16 years ago
    [hidden]

    Those notes were fucking hilarious!

    0 Reply
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    Yernat
    about 16 years ago
    [hidden]

    Altough its seems Ange is really stupid

    0 Reply
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    fcma172
    about 16 years ago
    [hidden]

    Is it bad that I can only solve 5 of those cause I can't understand WTF they wrote for the top 3?

    0 Reply
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    Dr Fine Rolo
    about 16 years ago
    [hidden]

    The top 3 are from Calc 2.

    -1 Reply
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    twerp
    about 16 years ago
    [hidden]

    Seriously, she's that much of a retard in the story?

    -1 Reply
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    FeKa
    about 16 years ago
    [hidden]

    Nope.

    0 Reply
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    fcma172
    about 16 years ago
    [hidden]

    Dr_Fine_Rolo said:
    The top 3 are from Calc 2.

    Well I never took Calculus so I feel less dumb now. ^_^

    0 Reply
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    Dr Fine Rolo
    about 16 years ago
    [hidden]

    Actually the integral is pretty easy and would be calc 1. Most books don't get into sums until calc 2 though. e^ipi is just an identity you probably don't need until calc2/3 or Diff Eq, depending.

    0 Reply
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    RumittanceWuzHere111
    about 16 years ago
    [hidden]

    e^iPi isn't even a problem, its just something used to transform between various things. Its just -1, after all.

    (that totally freaked me out when I first discovered that. Who would expect that taking e and raising it to i times Pi would be NEGATIVE ONE of all the damn things?!)

    2 Reply
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    NeverGonnaGive
    over 15 years ago
    [hidden]

    Would anyone have interest in overlaying the wrong answers with the right ones?

    0 Reply
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    furinkan
    over 15 years ago
    [hidden]

    T5J8F8 said:
    Would anyone have interest in overlaying the wrong answers with the right ones?

    Overlay is probably overkill, but the answers are simple enough (I hope I got these right, it's been a while... -_-).

    • e^(i*Pi) = -1
    • 62 + (2/3)
    • I forget the formal expression of this, but the limit approaches 2
    • 4x^2 + 4x + 1
    • 3 + (11/12)
    • 2048
    • 63
    1 Reply
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    DasMENTOR
    over 15 years ago
    [hidden]

    wtf is wrong with you guys?!

    -2 Reply
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    glasnost
    over 15 years ago
    [hidden]

    Translation note said:
    Eugh, could this be a mathematical pun on limits..?

    No, that's 極限 (kyokugen) in Japanese, not 程 (hodo).

    0 Reply
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    BobTheWaitress
    about 15 years ago
    [hidden]

    There's a naked chick in the picture and you guys are talking about algebra?

    5 Reply
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    Trucidation
    over 14 years ago
    [hidden]

    Because naked chicks are more easily found here than algebra.

    16 Reply
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    lordcross
    over 14 years ago
    [hidden]

    gladwort said:
    Crap. *leaves all his garments on the table and walks away naked, throwing hands in the air*
    Fucking algebra.

    This is win.

    -5 Reply
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    EMUltra3
    about 14 years ago
    [hidden]

    Strip Algebra? Pfft, make it strip calculus and I'm game.

    5 Reply
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    JakeBob
    about 14 years ago
    [hidden]

    ROMaster2 said:
    Strip Algebra? Pfft, make it strip calculus and I'm game.

    I prefer strip quantum physics.

    5 Reply
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    amiga49
    almost 14 years ago
    [hidden]

    Wow. Some of those I can grasp getting wrong. Like the problems at the top, but the ones at the bottom? 9 * 7 = 16? Seriously?

    0 Reply
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    Chucu
    almost 9 years ago
    [hidden]

    "e^(i*Pi) = eっ2"
    Seriously, what's this?

    0 Reply
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    FlameTroll
    almost 4 years ago
    [hidden]

    furinkan said:

    Overlay is probably overkill, but the answers are simple enough (I hope I got these right, it's been a while... -_-).

    • e^(i*Pi) = -1
    • 62 + (2/3)
    • I forget the formal expression of this, but the limit approaches 2
    • 4x^2 + 4x + 1
    • 3 + (11/12)
    • 2048
    • 63

    It might be overkill, but I did it anyway for the ones I understood in order to show readers how to get the correct answers. I was good at math when I was in school, but I didn't take university-level courses on these subjects and wasn't taught the more advanced concepts in high school, so I don't know the second and third ones (I found Euler's identity by accident while taking a Wiki Walk online some time ago).

    1 Reply
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    JackBonhomie
    almost 3 years ago
    [hidden]

    Poor girl, being humiliated in front of her class then having it posted to the internet, whose first reaction is to start discussing her answers. Who would be tactless enough to do such a thing‽ Anyways, I added explanations to the second and third questions. Could someone smarter than me have a look at them?

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    GO TO grade school
    The hell is this...
    Whaaaa...
    Even idiocy has limits.
    SERIOUSLY, DIE!
    This is way too stupid
    Garbage
    So stupid it's amazing
    She just added them lololol There's a pink arrow behind her back pointing to 9x7
    How do you even go shopping??
    The numerators and denominators of the fractions were incorrectly added together without first multiplying them to reach the least common multiple of the denominators. The correct answer is as follows: 2 (1 / 4) + 1 (2 / 3) = [Original equation] 2 (3 / 12) + 1 (8 / 12) = [Multiply 1 / 4 (both numbers, to keep its value the same) by 3 and multiply 2 / 3 (both numbers again) by 4 so that both denominators equal 12] 3 (11 / 12) [NOW you add the numerators of the fractions BUT NOT the denominators; if the numerator is greater than or equal to the denominator, subtract the denominator from the numerator and add 1 to the whole number as needed (not needed here)]
    9 * 7 = 63. 9 + 7 = 16.
    What is e? The correct answer is -1. Euler's identity is the mathematical formula "e ^ (π * i) + 1 = 0" where e is Euler's number (the base for natural logarithms [ln]), π (pi) is a circle's diameter divided by its circumference (always almost equals 3.14), and i is the "imaginary unit" which provides "i ^ 2 = -1" with an answer.
    Division by the fraction was incorrectly applied to the base of the exponent instead of being properly converted to multiplication by an integer and applied to the exponent. The correct answer is as follows: 2 ^ 10 / 0.5 = [Original equation] 2 ^ 10 * 2 = [Division by a fraction equals multiplication by its reciprocal except for 0 (which has no reciprocal)] 2 ^ 11 = [Multiplying by the base of the exponent increases the exponent by 1; multiplying by a power of the exponent increases the exponent accordingly] 2048 [The correct answer]
    Assuming the little white tint at the tip of her hair isn't more writing on the chalkboard behind her, the exponent was incorrectly applied to 2 and x separately instead of treating 2x as a single unit. The correct answer is as follows: (2x + 1) ^ 2 = [Original equation] (2x + 1) * (2x + 1) = [Expanding the exponent into multiplication] ( (2x * 2x) + (1 * 2x) ) + ( (2x * 1) + (1 * 1) ) = [First multiply the first unit within the first parenthesis group by each unit within the second parenthesis group, then multiply the second unit within the first parenthesis group by each unit within the second parenthesis group), before finally adding the two groups together] (4x^2 + 2x) + (2x + 1) = [Because 2 is an integer while x is a variable, 2 can be squared to 4 but x^2 must be presented in variable-and-exponent form] 4x^2 + 4x + 1 [The correct answer]
    This is a summation equation. The bottom states what i starts out equal to, and the top states when the summation stops (in this case, the summation never stops). ∑∞ᵢ ₌ ₀ ¹/₂ = (¹/₂)⁰ + (¹/₂)¹ + (¹/₂)² ⋯ + (¹/₂)^∞ = 1 + ¹/₂ + ¹/₄ ⋯ = 1 + ∑∞ᵢ ₌ 1 ¹/₂ Since ∑∞ᵢ ₌ ₁ ¹/₂ = 1, = 1+1 = 2 Miss Ushiromiya has just substituted the i in (¹/₂)ⁱ with i=0. Her answer is also not simplified (it should be 1 as (¹/₂)⁰=1).
    This is a (definite) integration equation, part of calculus, which among other things can be used to find the area under a curve. When one integrates (definitely), we increase the exponent of 𝑥 by one then divide it by the new exponent (∫²₁ 𝑥d𝑥 = [¹/₂*𝑥²]²₁), then replace 𝑥 with the top number and bottom number and subtract the two ([¹/₂*𝑥²]²₁ = [¹/₂*2²]-[¹/₂*1²] = [2]-[¹/₂] = 1¹/₂). ∫³₋₁ (𝑥³+2𝑥²+6)d𝑥 By the addition rule of integration, = ∫³₋₁ (𝑥³)d𝑥 + ∫³₋₁(2𝑥²)d𝑥 +∫³₋₁ (6𝑥⁰)d𝑥 By the constant multiple rule of integration, = ∫³₋₁ (𝑥³)d𝑥 + 2∫³₋₁(𝑥²)d𝑥 + 6∫³₋₁ (𝑥⁰)d𝑥 = [¹/₄*𝑥⁴]³₋₁ + 2[¹/₃*2𝑥³]³₋₁ + 6[¹/₁*𝑥¹]³₋₁ By the constant multiple rule of integration, = ¹/₄[𝑥⁴]³₋₁ + (2*¹/₃)[2𝑥³]³₋₁ + (6*1)[𝑥¹]³₋₁ = ¹/₄[3⁴-(-1)⁴] + ²/₃[3³-(-1)³] + 6[3¹-(-1)¹] = ¹/₄[81-1] + ²/₃[27-(-1)] + 6[3-(-1)] = ¹/₄[80] + ²/₃[28] + 6[4] = 20 + ²⁸/₃ + 24 = ¹⁸⁸/₃ = 62²/₃ The addition rule of integration states that '∫ f(𝑥) + g(𝑥)d𝑥 = ∫ f(𝑥)d𝑥 + ∫ g(𝑥)d𝑥.' That is to say, an integral of a sum of functions is equal to the integrals of the individual bits of that sum. The constant multiple rule of integration states that 'if k is constant, ∫ kf(𝑥)d𝑥 = k∫ f(𝑥)d𝑥.' f(𝑥) represents a function of 𝑥. 𝑥, 7𝑥, (3𝑥+2)(𝑥-2) can all be represented by f(𝑥) ...I'm not entirely sure how Miss Ushiromiya here got 14.
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